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Timeline for Field of Values and Eigenvalues

Current License: CC BY-SA 3.0

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May 9, 2011 at 20:25 comment added Denis Serre It might be. We know that the numerical radius $r(A)$, which is the radius of the smallest disk containing $W(A)$, satisfies $r(A)\ge\frac12\|A\|$. Besides, $\|A\|$ is the largest singular value. Therefore, if the eigenvalues are all zero, we have that the distance of $\lambda=0$ to $\partial W(A)$ is larger than or equal to half the largest singular value.
May 9, 2011 at 17:39 history asked fkenter CC BY-SA 3.0