Timeline for Field of Values and Eigenvalues
Current License: CC BY-SA 3.0
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May 9, 2011 at 20:25 | comment | added | Denis Serre | It might be. We know that the numerical radius $r(A)$, which is the radius of the smallest disk containing $W(A)$, satisfies $r(A)\ge\frac12\|A\|$. Besides, $\|A\|$ is the largest singular value. Therefore, if the eigenvalues are all zero, we have that the distance of $\lambda=0$ to $\partial W(A)$ is larger than or equal to half the largest singular value. | |
May 9, 2011 at 17:39 | history | asked | fkenter | CC BY-SA 3.0 |