Timeline for Why hasn't mereology succeeded as an alternative to set theory?
Current License: CC BY-SA 3.0
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| Dec 8, 2017 at 8:28 | comment | added | მამუკა ჯიბლაძე | There is also the unary operator $s$ which is needed to define membership, and I would say in a sense having this operator is equivalent to having membership defined. | |
| May 9, 2011 at 1:37 | history | edited | Sridhar Ramesh | CC BY-SA 3.0 |
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| May 9, 2011 at 0:12 | history | edited | Sridhar Ramesh | CC BY-SA 3.0 |
added 646 characters in body; added 4 characters in body; deleted 28 characters in body; added 37 characters in body; edited body; deleted 2 characters in body; added 3 characters in body
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| May 9, 2011 at 0:04 | history | answered | Sridhar Ramesh | CC BY-SA 3.0 |