Skip to main content
14 events
when toggle format what by license comment
Feb 7, 2022 at 2:56 comment added Jose Arnaldo Bebita @LuisHGallardo: Apologies for bumping this question from May 2011 to the front page, but do you happen to know if the case of even $m$ and odd $n$ has been ruled out?
Aug 11, 2013 at 2:34 answer added Jose Arnaldo Bebita timeline score: 0
May 10, 2011 at 17:51 vote accept Luis H Gallardo
May 9, 2011 at 0:34 history edited Luis H Gallardo CC BY-SA 3.0
added 87 characters in body
May 9, 2011 at 0:33 comment added Luis H Gallardo Thanks, no problem; Probably the question was also not completely clear... I will edit it a little.
May 9, 2011 at 0:19 comment added Todd Trimble Well, I've looked at it a little longer, and I guess I spoke too soon, and I owe you an apology.
May 9, 2011 at 0:18 comment added Luis H Gallardo Do you really have a solution with odd $n$ ???? should be published.
May 9, 2011 at 0:16 comment added Luis H Gallardo Think a little harder Todd Trimble !
May 9, 2011 at 0:03 comment added Luis H Gallardo add your answer to gerry's in order to have a complete solution then...
May 9, 2011 at 0:01 comment added Todd Trimble Think a little harder, Luis Gallardo.
May 8, 2011 at 23:58 answer added Gerry Myerson timeline score: 3
May 8, 2011 at 23:57 comment added Luis H Gallardo false: since you take $n$ even, but it may be odd ...
May 8, 2011 at 23:53 comment added Todd Trimble I really think this is too elementary for this site. The short answer to your question is 'no'. It follows very easily from the binary representation of <a href="en.wikipedia.org/wiki/… perfect numbers</a>. Alternatively, you might try your question over at math.stackexchange.com.
May 8, 2011 at 23:40 history asked Luis H Gallardo CC BY-SA 3.0