Timeline for How much larger is the powerset of a transfinite set?
Current License: CC BY-SA 3.0
14 events
| when toggle format | what | by | license | comment | |
|---|---|---|---|---|---|
| May 10, 2011 at 15:22 | answer | added | Samuel Coskey | timeline score: 3 | |
| May 10, 2011 at 4:37 | vote | accept | P. Brooks | ||
| May 9, 2011 at 5:36 | answer | added | user13113 | timeline score: 0 | |
| May 9, 2011 at 1:46 | comment | added | Michael Hardy | I think it's better not to phrase it as a proof by contradiction. Instead of saying "Suppose there is a bijection", say "Consider any injection", and then show that it misses some points. | |
| May 8, 2011 at 20:10 | comment | added | Todd Trimble | @P. Brooks: I've tried to answer your most edit (although it really feels like I'm repeating the point that Jason tried to make). | |
| May 8, 2011 at 19:59 | answer | added | Clinton Conley | timeline score: 9 | |
| May 8, 2011 at 18:26 | history | edited | P. Brooks | CC BY-SA 3.0 |
added 1884 characters in body
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| May 8, 2011 at 7:53 | answer | added | Pete L. Clark | timeline score: 0 | |
| May 8, 2011 at 7:24 | comment | added | Asaf Karagila♦ | If you try to impress them in the largeness of a "bigger cardinality" just try and give them the idea how far from $\aleph_0$ is $\aleph_1$, that no matter how far you went - if you only walked a countable number of steps from $\omega$ then you are still countable. This is a stepping stone in understanding how big is the difference in cardinalities, from here explain vaguely that the power set can be almost anything larger, so it must be vastly larger. | |
| May 8, 2011 at 6:29 | answer | added | Jason | timeline score: 3 | |
| May 8, 2011 at 4:08 | answer | added | Stefan Geschke | timeline score: 7 | |
| May 8, 2011 at 0:57 | answer | added | Todd Trimble | timeline score: 9 | |
| May 8, 2011 at 0:25 | answer | added | Nate Eldredge | timeline score: 22 | |
| May 7, 2011 at 23:59 | history | asked | P. Brooks | CC BY-SA 3.0 |