Timeline for What is $\overline{\text{Spec}\mathbb{Z}}$?
Current License: CC BY-SA 2.5
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Jul 22, 2018 at 22:15 | comment | added | S. Carnahan♦ | @Qfwfq The generic point corresponds to the prime $(0)$, which normally corresponds to the trivial absolute value $|x|_0 = 1-\delta_{x,0}$. On the other hand, the preimage of the generic point along the canonical map from the Berkovich spectrum contains everything except the endpoints $|-|_p^\infty$. | |
Jul 22, 2018 at 20:50 | comment | added | Qfwfq | I just came across this post now - maybe someone around or the OP himself may still answer though :-) "Z has a valuation that is not captured by the points of the topological space, namely the usual Archimedean absolute value" - I have a naive question: isn't the generic point of SpecZ meant to correspond to the Archimedean absolute value on Z? | |
Nov 23, 2009 at 15:20 | vote | accept | Abtan Massini | ||
Nov 22, 2009 at 1:17 | history | answered | S. Carnahan♦ | CC BY-SA 2.5 |