Timeline for Pythagorean 5-tuples
Current License: CC BY-SA 3.0
2 events
| when toggle format | what | by | license | comment | |
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| May 7, 2011 at 13:05 | comment | added | mikhail skopenkov | Thank you for a nice parametrization. This fits well the approach of Geoff Robinson. If S=s+1+i(s-1), T=t+1+j(s-1), U=u+1+k(u-1) and STUUTS=v+ix+jy+kz then ( x,y,z,v,(s^2+1)(t^2+1)(u^2+1) ) coincides with your solution. | |
| May 6, 2011 at 16:44 | history | answered | doetoe | CC BY-SA 3.0 |