Skip to main content

Timeline for $G$-structures of finite type.

Current License: CC BY-SA 3.0

8 events
when toggle format what by license comment
May 6, 2011 at 0:39 vote accept Leandro
May 6, 2011 at 0:00 comment added André Henriques @Olivier: I think that you're correct. And I think that having a structure of order 3 would mean the following: there should exist a $G$-manifold $M$, and a non-trivial (locally-defined) automorphism around some point $m\in M$ that fixes the 2-jet of that point.
May 5, 2011 at 23:56 answer added Robert Bryant timeline score: 15
May 5, 2011 at 23:54 comment added Olivier Bégassat when you write $\mathbb{R}^n$ do you mean $T_m M$, the tangent space at $m\in M$? Is your notion of $G$ structure the same as that where you ask for an atlas of $M$ such that the transition maps induced on the local trivialisations of $TM$ act like $G$ (for some representation $\roh:G\rightarrow \mathrm{GL}(n)$?
May 5, 2011 at 23:48 history edited André Henriques CC BY-SA 3.0
added 231 characters in body
May 5, 2011 at 23:35 comment added Leandro Actually, while the definition involves the bundle $B_G$, it depends only on the group $G$. You may think of $\mathfrak{g}^{(k)}$ as the space of all $k+1$-multilinear functions $T : (\mathbb{R}^n)^{k+1} \rightarrow \mathbb{R}^n$ which are completely symmetric and such that, given any $v_1, \ldots, v_k \in \mathbb{R}^n$, the linear map $\phi : \mathbb{R}^n \rightarrow \mathbb{R}^n$ given by $\phi(u) = T(v_1, \ldots, v_k, u)$ belongs to $\mathfrak{g}$.
May 5, 2011 at 23:28 comment added Olivier Bégassat could you explain the meaning of $\mathfrak{g}^{(k)}$? and its relation to $\pi$?
May 5, 2011 at 23:25 history asked Leandro CC BY-SA 3.0