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May 20, 2011 at 20:22 vote accept CommunityBot
May 20, 2011 at 20:22 history bounty ended TMM
May 20, 2011 at 19:59 answer added Gerhard Paseman timeline score: 0
May 17, 2011 at 20:04 answer added Thomas Kalinowski timeline score: 2
May 17, 2011 at 18:28 answer added Clinton Conley timeline score: 2
May 17, 2011 at 15:13 comment added Clinton Conley For every $c$ it's not too hard to build a corresponding $\mathcal{S}$ with $r(\mathcal{S})$ approximately equal to $4/c$. The exact value for the construction I have in mind depends a tiny bit on the parity. So I guess you should aim to do better than that.
May 17, 2011 at 12:09 history edited TMM CC BY-SA 3.0
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May 17, 2011 at 12:07 comment added TMM Thanks kali, that was easier than I thought (why didn't I think of that?). At least this gives an upper bound on $f(c)$, for prime powers $c - 1$. For the application I'm using it for it is most important to show that $f(c)$ becomes really small as $c$ becomes large, so such an upper bound (even with gaps) would already be a somewhat nice result. But of course in general it is an interesting question whether we can prove that $f(c)$ is minimized when $S$ is a proj. plane (and whether it is true). For $c - 1 \neq p^m$ I'm not sure how to continue, or what $f(c)$ should be.
May 17, 2011 at 1:20 comment added Thomas Kalinowski I'm not quite sure what "over $\mathbb{F}_2$ should mean, but the rate of a projective plane of order c-1 is indeed $c/(c^2-c+1)$. To see this let $V$ be any subset of the point set. We just have to show that there is a line $L$ such that $|V\cap L|/|V|\leqslant c/(c^2-c+1)$. Now suppose that's not the case, i.e. $|V\cap L|> c|V|/(c^2-c+1)$ for every line $L$. Summing over the lines we obtain $$\sum_{L}|V\cap L|>c|V|.$$ But on the left hand side every element of $V$ is counted $c$ times, so the LHS is equal to $c|V|$, contradiction. By th way, what's your plan for $c$'s without proj. planes?
May 14, 2011 at 23:50 history edited TMM CC BY-SA 3.0
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May 13, 2011 at 19:31 history bounty started TMM
May 11, 2011 at 9:49 history edited TMM CC BY-SA 3.0
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May 10, 2011 at 21:26 history edited TMM CC BY-SA 3.0
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May 9, 2011 at 12:25 comment added Clinton Conley I don't know if this is at all useful (and it's possibly well known?), but you can in some sense uniformly finitize the problem. If $\mathcal{S}$ is a $c$-uniform pairwise intersecting set system and some $u \in U$ is in more than $c^{c-1}$ elements of $\mathcal{S}$, then $r(\mathcal{S}) \geq 1/(c-1)$ which (if my arithmetic is correct) is already above the bound given by the projective plane of order $(c-1)$. This gives explicit finite bounds on $|U|$ and $|\mathcal{S}|$ (in terms of $c$) for potential counterexamples.
May 9, 2011 at 8:41 answer added Thomas Kalinowski timeline score: 0
May 6, 2011 at 19:55 comment added Gerhard Paseman Regarding matroids, no I cannot. I was initially thinking of picking a set $D$ in $S$ and using it to classify sets in S, using the fact that for any partition $E \cup F$ of $D$, any set in $S$ which intersects $D$ in $G \subseteq E$ must intersect any other set in $S$ which intersects $D$ in $H \subseteq F$, and using that to classify the isomorphism types of set systems $S$, but I know of no clean way to proceed after that. While finite combinatorial designs may ultimately be what you want, I can't guarantee finite. Thus matroids. Gerhard "Ask Me About System Design" Paseman, 2011.05.06
May 6, 2011 at 18:23 comment added TMM Could you be a bit more specific? I am not that familiar with matroid theory, but I don't see how formulating this as a matroid problem makes the problem easier. Actually at first I was hoping that this "maximality" of projective planes was some obvious property I did not know about, but apparently it is not...
May 5, 2011 at 21:56 comment added Gerhard Paseman I imagine matroids may be useful here. Perhaps searching the web for your favorite terms with "matroid" is worth a few minutes of your time. Gerhard "Ask Me About System Design" Paseman, 2011.05.05
May 5, 2011 at 18:07 history edited TMM CC BY-SA 3.0
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May 5, 2011 at 15:06 history asked TMM CC BY-SA 3.0