Timeline for Third bordism group of BG, where G is an arbitrary compact Lie group.
Current License: CC BY-SA 3.0
6 events
when toggle format | what | by | license | comment | |
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Apr 30, 2011 at 19:09 | comment | added | Kevin Wray | Wait, I thought I'd read somewhere that $\Omega_3(BG)$ was equivalent to $H_3(BG)$ up to torsion. | |
Apr 30, 2011 at 6:57 | comment | added | Torsten Ekedahl | The unoriented case is even simpler as unoriented bordism is just homology with coefficients in the (unoriented) bordism ring. | |
Apr 30, 2011 at 3:30 | comment | added | Sean Tilson | @Dylan: I think the exact couple set up makes it reasonably clear. Have you looked at Adams? | |
Apr 30, 2011 at 2:54 | comment | added | Dylan Wilson | Is it obvious that Atiyah-Hirzebruch applies to the associated homology of a spectrum in the same way as the associated cohomology? | |
Apr 29, 2011 at 22:30 | comment | added | Kevin Wray | Thank you! Can you say anything as nice for the unoriented case? | |
Apr 29, 2011 at 21:46 | history | answered | Johannes Ebert | CC BY-SA 3.0 |