Timeline for How to write down the determinant of a quasi-isomorphism?
Current License: CC BY-SA 3.0
6 events
| when toggle format | what | by | license | comment | |
|---|---|---|---|---|---|
| May 21, 2011 at 6:08 | comment | added | jlk | @Yuija Qiu: Sorry for the delayed response. I am slightly confused by your your final conclusion. The vector spaces $F_0$ and $S_0$ could have different dimensions (and similarly for $F_1$ and $S_1$). The fact that the complexes are quasi-isomorphic only tells us that $\operatorname{dim}(F_1) - \operatorname{dim}(F_0) = \operatorname{dim}(S_1) - \operatorname{dim}(S_0)$. When the dimensions are different, what is meant by $\operatorname{det}(F_0)$? | |
| May 6, 2011 at 4:24 | comment | added | jlk | @Yujia Qiu: Thanks for the response! I have not thought about this question in a bit. I will try to think about your answer over the weekend. | |
| Apr 29, 2011 at 17:19 | history | edited | Yujia Qiu | CC BY-SA 3.0 |
added 14 characters in body; added 33 characters in body
|
| Apr 29, 2011 at 16:33 | comment | added | Yujia Qiu | i don't know why this looks like a mess, sorry for the inconveniece :( | |
| Apr 29, 2011 at 16:32 | history | edited | Yujia Qiu | CC BY-SA 3.0 |
deleted 26 characters in body
|
| Apr 29, 2011 at 16:27 | history | answered | Yujia Qiu | CC BY-SA 3.0 |