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Oct 24, 2009 at 15:47 answer added Benjamin Antieau timeline score: 3
Oct 17, 2009 at 14:20 comment added Andy Putman I forgot to mention one thing which should be kept in mind. Serre's GAGA paper says that if M is a COMPACT complex manifold, then M can be given an algebraic structure in at most one way. Thus the M that Georges supplied was by necessity noncompact.
Oct 17, 2009 at 4:45 comment added Andy Putman A fancier thing one could say is that the moduli space of algebraic structures on a complex manifold can contain more than one point. I wonder how large it can be?
Oct 17, 2009 at 4:44 comment added Andy Putman The key point is that this is not exactly a question about abstract algebraic geometry. Rather, I am looking for (and, fact, found -- see Georges's comment below) a complex manifold M that can be "stiffened up" to be a quasiprojective variety in two different ways. On a naked complex manifold, there is no notation of things being "algebraic", only holomorphic. The example given by Georges says that knowing which things are "algebraic" is really new information that cannot be gleaned from the complex structure.
Oct 16, 2009 at 21:10 comment added shenghao I'm afraid I don't understand the question. In abstract algebraic geometry, things like the sheaf of regular functions and the Picard group of a variety M are intrinsic, so they should not depend on the projective embedding of M. But one can have two independent ample line bundles, which give two projective embeddings. Is that what you mean: find M such that Pic(M) is large, and the ample cone is not just a ray?
Oct 16, 2009 at 2:43 vote accept Andy Putman
Oct 15, 2009 at 20:52 answer added Georges Elencwajg timeline score: 22
Oct 15, 2009 at 19:10 history asked Andy Putman CC BY-SA 2.5