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May 1, 2011 at 4:31 vote accept Marty
Apr 29, 2011 at 14:53 comment added Marty Thank you for getting this started. Perhaps I'll use an upsilon for the first time since Greek class.
Apr 29, 2011 at 7:15 comment added Igor Khavkine Great to hear that you've found the answer. A tiny comment though is that Gillman and Jerison insist that the realcompactification notation $\upsilon$ is an upsilon and not a v. :-)
Apr 29, 2011 at 6:40 comment added Marty The proof finishes: A unital continuous ring homom $\phi$ from $C(Y)$ to $C(X)$ determines a unique continuous map $f$ from $X$ to $vY$ such that for all $g \in C(Y)$, and all $x \in X$, $g^v(f(x)) = (\phi(g))(x)$ by Thm 10.8 of Gillman-Jerison (here $g^v$ is the extension of $g$ to $vY$). The map $ev_x \circ \phi$, sending $g \mapsto (\phi(g))(x)$ is continuous since $\phi$ is continuous and evaluation at $x$ is continuous. All such continuous functionals on $C(Y)$ arise from evaluation at some (unique) $y \in Y$, when $Y$ is loc.cpt. (R.E.Edwards,1957,Mathematika). So $f(x) = y \in Y$.
Apr 29, 2011 at 3:14 comment added Marty Theorem 10.8 (with your comments) goes most of the way towards what I want. Thank you again! I think I'll check in some earlier papers of Hewitt, and see if I can finish off the proof.
Apr 29, 2011 at 0:07 comment added Marty When I say "rings", I mean unital rings (and unital homomorphisms). I definitely don't want any connectedness hypothesis. But thank you for the Theorem 10.8 reference. I'll check it out this evening.
Apr 29, 2011 at 0:03 history answered Igor Khavkine CC BY-SA 3.0