Edit: The question is whether a particular descriptionfirst version of this answer proposed a numbercriterion based on Kolmogorov complexity, but as Scott Aaronson commented, this is "concrete" enoughnot very restrictive since primes all have rather low complexity: primality not being very hard to considerdesign an inefficient test for, the number "known" from it; one could sayn'th prime $p_n$ has complexity at most $\log n \approx \log\log p_n$. It appears that thiswhat I had in mind was more or less what he wrote in his answer.
However, it seems to me that the issue of complexity is accomplished if wepart of what makes the question interesting: extremely large numbers should be expected to have locatedextremely large complexity, and it is the number precisely withindisparity between the linear orderinglow complexity of all numbers. For practical purposes, that means giving a decimal expansion some short description like C(or binary expansion, which is theoretically and computationally equivalent5). Although most and the high complexity of the other answers endorse some criterion like "the algorithm must outputdigit string of C(5) itself which makes the expansion in polynomial time"description seem not to be concrete. More generally, that seems either unnecessarily restrictive or unnecessarily generous depending on your position onone may doubt the knowability of veryextremely large numbers (generous, in that evenon the theoretical best timegrounds that they cannot be written explicitly, logarithmicas stated in the size ofquestion.
So contrary to the number,claim that C(5) is not good enougha concrete description of a number, I think that due to really describe truly large numbers; restrictiveits low complexity it is much more concrete than its size would suggest, and its base-2 digits are easily listed; most numbers of its magnitude are wholly abstract and their digits in that you might feelany base will never be known. In fact, I am not entirely sure that being able to compute thea prime-enumerating algorithm which computes C(5) in time polynomial in C(4) (its number of binary digits at all), as Scott suggests, is enoughactually especially concrete, unless it takes an input significantly smaller than C(5) (note that C(5) is about the C(5)'th prime).
It does seem like saying "the $10^{10^{10000}}$'th prime"That is somehow cheating, though. It's too short! It's barely better than saying "that prime, you know which one I mean"a computation may be efficient without being concrete. Thus In the spirit of Alastair Litterick's answer, I wouldI'd like to propose the criterionsuggest that
An enumeration of description of numbers,algorithm for example "the numberlisting $2^n - 1$" or "the n'th prime", generates "known" numbers if the Kolmogorov complexity of the decimal expansions(some infinite family of the numbers themselves) primes which is polynomialefficient in the complexitysense of the corresponding descriptions. ThatScott's answer is, there exists a polynomial p(c), depending only on also "concrete" if the enumeration, such that for a particular descriptionlength of complexity c,its output is superpolynomial in the number it describes has complexity at most p(c)length of its input.
That isMore generally, a description is "cheating" ifI suppose it does not provide any significant information aswould make sense to the identity of the number it specifies. Alas, Kolmogorov complexity seems rather nonconstructive as a criterion.
Note that my position is then that saying "the numbers C(n), where for all k we define $C(k + 1) = 2^{C(k)} - 1$ and C(0) = 2" is not cheating, since the obvious description "C(n - 1) 1's in base 2, where C(k + 1) = ..." has basically the same complexity (both are linear in that of n). Onquantify just how much larger the other hand, "the n'th prime"output is probably cheating, since even for $n = 2^k$, the complexity of whose digits is at most $\log k = \log \log n$, the best way we havepurposes of finding $p_n$ is just an exhaustive search, which is worse than linear in n; $n = 2^{2^k}$ is even more extreme.
Of course, a decent prime-listing algorithm would improve this, though probably not enough to be iterated-logarithmic. For this reason, I like Alastair Litterick's answerprobing very distant primes.