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Timeline for Definition of "simplicial complex"

Current License: CC BY-SA 2.5

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Feb 1, 2013 at 15:01 comment added John Rognes @StB: Nope -- any subdivison of $\Delta[2]$ will contain a triangle that meets $\partial\Delta[2]$ along an edge, and then the map from that triangle to $\Delta[2]/\partial\Delta[2]$ is not an embedding.
May 23, 2012 at 3:19 comment added Spice the Bird I think that a double barycentric subdivision will always work.
Nov 20, 2009 at 17:02 history answered Charles Rezk CC BY-SA 2.5