Timeline for Is $PSL(n, Z)$ isomorphic to a subgroup of $GL(n,C)$ or even $GL(n+1,C)$?
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| Apr 24, 2011 at 9:05 | comment | added | Alain Valette | What Margulis superrigidity tells you is that a homomorphism $SL_n(\mathbb{Z})\rightarrow GL_m(\mathbb{C})$ is a direct sum of a homomorphism extending to $SL_n(\mathbb{R})$ and of a homomorphism factoring through some congruence subgroup. | |
| Apr 23, 2011 at 23:16 | history | answered | Randy Boas | CC BY-SA 3.0 |