Timeline for Can an infinite conjugacy class in a group split into more than one conjugacy class in some subgroup of finite index?
Current License: CC BY-SA 2.5
10 events
| when toggle format | what | by | license | comment | |
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| Nov 21, 2009 at 7:14 | comment | added | Kevin Buzzard | "in general is there a conj class that splits into more than one in some subgroup?". In general, yes. | |
| Nov 21, 2009 at 1:41 | comment | added | yeshengkui | But in general, is there a conjugacy class splits into more than one in some subgroup? In abelian group, there is no such conjugacy class. Actually, I want to know whether there some theorems related this. | |
| Nov 21, 2009 at 1:36 | vote | accept | yeshengkui | ||
| Nov 22, 2009 at 9:09 | |||||
| Nov 21, 2009 at 1:36 | vote | accept | yeshengkui | ||
| Nov 21, 2009 at 1:36 | |||||
| Nov 20, 2009 at 19:01 | comment | added | Kevin Buzzard | Take any conjugacy class in any group that splits into more than one class in a subgroup (of finite index if you like). And now just take the product of the entire situation with a group with an infinite conjugacy class? What am I missing? | |
| Nov 20, 2009 at 18:16 | history | edited | S. Carnahan♦ | CC BY-SA 2.5 |
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| Nov 20, 2009 at 14:26 | vote | accept | yeshengkui | ||
| Nov 20, 2009 at 14:26 | |||||
| Nov 20, 2009 at 14:26 | vote | accept | yeshengkui | ||
| Nov 20, 2009 at 14:26 | |||||
| Nov 20, 2009 at 13:48 | answer | added | Simon Wadsley | timeline score: 10 | |
| Nov 20, 2009 at 13:41 | history | asked | yeshengkui | CC BY-SA 2.5 |