Timeline for Integral identity for Legendre polynomials
Current License: CC BY-SA 3.0
4 events
| when toggle format | what | by | license | comment | |
|---|---|---|---|---|---|
| Apr 21, 2011 at 11:05 | answer | added | Bob Yuncken | timeline score: 4 | |
| Apr 21, 2011 at 10:30 | comment | added | user11235 | $$\int_0^1 \frac 1 {\sqrt{1-2(2x^2-1)t^2+t^4}}dx = \frac {\arctan t} t$$ might work even better. | |
| Apr 21, 2011 at 9:30 | comment | added | darij grinberg | By means of power series, this transforms into something like $\int\limits_0^1\dfrac{1}{\sqrt{1-2\left(2x^2-1\right)t+t^2}}dx=\mathrm{arctan}t$ (note that I have changed your $t$ into an $x$). Maybe it's easier this way? | |
| Apr 21, 2011 at 9:06 | history | asked | Bob Yuncken | CC BY-SA 3.0 |