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May 26, 2011 at 18:27 comment added Syed @Felipe I read in this paper: arxiv.org/abs/math/0205314 at top of page 2: A curve with large automorphism group always has orbit genus 0. Large means |Aut(C)| > |4(g-1)|.
Apr 21, 2011 at 0:39 comment added Felipe Voloch I don't think you'll be able to do it without looking at ramification.
Apr 20, 2011 at 19:34 comment added Syed I mean I need Ramification structure, is it possible to just using $Aut(F/K)$ and $G$ we can compute the genus of $F^G$?
Apr 20, 2011 at 19:32 comment added Syed How is genus of $F^G$ computable if all I have is the automorphism group?
Apr 20, 2011 at 2:51 history answered Felipe Voloch CC BY-SA 3.0