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May 8, 2011 at 10:14 answer added Maciej Skorski timeline score: 1
Apr 18, 2011 at 8:41 answer added Denis Serre timeline score: 1
Apr 17, 2011 at 20:40 comment added Jennifer Gao @Suvrit: is it? The expression for the roots of a cubic looks pretty complicated to me, and the lower bound is just a pair of terms.
Apr 17, 2011 at 8:50 comment added Suvrit but computing the roots of your cubic don't seem to be too much more complicated than computing the lower bounds? en.wikipedia.org/wiki/Cubic_function
Apr 17, 2011 at 8:33 history edited Jennifer Gao CC BY-SA 3.0
Changed the convex combination
Apr 17, 2011 at 8:29 comment added Jennifer Gao Sorry, I don't understand -- how does the "splitting" work?
Apr 16, 2011 at 19:32 history edited Jennifer Gao CC BY-SA 3.0
Removed the bit about a 1.5 approximation
Apr 16, 2011 at 19:24 comment added Nishant Chandgotia can't you just split 1/x into the linear combination and use that.
Apr 16, 2011 at 19:20 history edited Jennifer Gao CC BY-SA 3.0
Added a caveat on a and b
Apr 16, 2011 at 19:15 history asked Jennifer Gao CC BY-SA 3.0