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Apr 17, 2011 at 6:33 comment added Kevin Wray Yes, I like your argument for injectivity and this is all that I need to show $H^{odd}(BG,\mathbb{R})=0$. Thanks.
Apr 17, 2011 at 2:19 history edited Andreas Holmstrom CC BY-SA 3.0
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Apr 16, 2011 at 18:39 history answered Johannes Ebert CC BY-SA 3.0