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Jul 10, 2011 at 16:15 history edited Seva CC BY-SA 3.0
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Apr 17, 2011 at 6:13 history edited Seva CC BY-SA 3.0
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Apr 17, 2011 at 1:49 answer added Aaron Meyerowitz timeline score: 1
Apr 15, 2011 at 14:28 comment added Seva @Maurizio: the vectors, generating $L$, are vectors of the form $e_1\otimes\dots\otimes e_n$, where $n-1$ of the vectors $e_i$ are equal to $(1,a)$, and one of these vectors is equal to $(a,-1)$. So, all vectors $e_i$ lie in $R^2$, and their product lies in $R^{2^n}$.
Apr 15, 2011 at 12:03 comment added Maurizio Monge What are the coordinates of a vector in $R^{2^n}$ (that should be defined uniformly in $n$, for your question to make sense), do you consider it as the $n$-th tensor power of $R^2$ and generated by the elements $e_{i_1}\otimes e_{i_2}\otimes \dots \otimes e_{i_n}$?
Apr 15, 2011 at 10:33 history asked Seva CC BY-SA 3.0