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Aug 20, 2020 at 13:30 answer added MathCrawler timeline score: 1
Feb 13, 2020 at 20:49 comment added Watson Related: "Bernoulli numbers and the unity of mathematics" by B. Mazur.
Apr 24, 2016 at 14:03 history edited Amir Sagiv
it is obviously a big-picture question. I think it has evolved to a big-list, and therefore will be more accesible with the tag
Aug 31, 2015 at 20:00 comment added ACL @gowers: As Douady says in his Algèbre et théorie galoisienne, beware of adverbs - « Nous ne supposons pas l'espace simplement connexe, nous le supposons simplement connexe. »
Dec 12, 2014 at 6:25 comment added Tom Copeland Generalized Bernoulli polynomials defined by powers of the e.g.f. (used in Hizebruch's criterion for the Todd class) have a rich history in the q-calculus as noted in Thomas Ernst's writings. Doyon, Lepowsky, Milas show how the Bernoulli polynomials are related to vertex operator algebras. The Bernoullis are related to the Euler, Eulerian, zizgag, Gennochi, ordered Bell numbers, and polylogarithms. Since the e.g.f. is tied so closely to exp, they occur in expansions of trig and hyperbolic functions. Quantum groups, solitons, and solns.of the KdV equation, I've noted elsewhere. Now shoes, ... .
Dec 10, 2014 at 20:07 comment added Tom Copeland Basically, where ever you see the derivative you could replace it with the Bernoulli polynomials and make some sense of it, but you are right, Ryan. I've never seen even one under my bed. Never seen an exponential there either. What was the OP thinking of?!
Dec 10, 2014 at 11:58 history edited user21574 CC BY-SA 3.0
added 16 characters in body
Dec 10, 2014 at 4:37 comment added Ryan Budney I suppose I don't agree with the premise. Bernoulli numbers, it seems clear to me, do not appear everywhere. They're relatively rare objects that come up in fairly particular circumstances. If they appeared everywhere, I imagine I would be seeing them more often.
Nov 27, 2014 at 2:37 history made wiki Post Made Community Wiki by Todd Trimble
Nov 20, 2014 at 6:35 answer added Zurab Silagadze timeline score: 4
Nov 19, 2014 at 23:02 answer added Lev Soukhanov timeline score: 2
Nov 18, 2014 at 19:30 answer added DavidLHarden timeline score: 6
Nov 18, 2014 at 17:51 answer added Tom Copeland timeline score: 4
Jun 27, 2014 at 0:33 comment added Tom Copeland @Michael, I think P. Cartier discusses that and more in "Mathemagics."
Jun 27, 2014 at 0:05 comment added Michael Hardy The also arise in the cumulants of the uniform distribution on the interval $[-1,1]$. If I recall correctly, the $n$th cumulant is $B_n/n$. ${}\qquad{}$
S Jun 26, 2014 at 20:25 history suggested F. C.
added the tag bernoulli numbers, obviously missing
Jun 26, 2014 at 20:15 review Suggested edits
S Jun 26, 2014 at 20:25
Oct 3, 2012 at 2:28 comment added Tom Copeland The Bernoulli numbers also occur in the solution of linear ODEs. See A. Iserles "Expansions that grow on trees."
Apr 11, 2011 at 17:42 history edited Charles Matthews CC BY-SA 3.0
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Apr 11, 2011 at 12:54 comment added Alex B. @Tim You are right, I guess I didn't mean simply connected, but rather a complete graph or something like that.
Apr 11, 2011 at 12:28 answer added Neil Strickland timeline score: 18
Apr 11, 2011 at 9:36 answer added Stefan Waldmann timeline score: 10
Apr 11, 2011 at 8:32 comment added gowers @Alex, I take it that by "simply connected" you mean "connected in a simple way".
Apr 11, 2011 at 7:33 answer added John Baez timeline score: 46
Apr 11, 2011 at 4:42 comment added Alex B. Just a minor remark: the space of the areas you have mentioned might be simply connected. For example, the criteria for regular primes, the zeta values at even integers, and higher K-theory - these are all closely related areas. If you are willing to take on board everything we know and everything we conjecture to be true, then it follows that Bernoulli numbers appear in one of these if and only if they appear in all of them. Somewhat related is my answer here: mathoverflow.net/questions/45376/…
Apr 11, 2011 at 4:19 comment added 36min That's a good point. So do you know how did he define it and what's his motivation?
Apr 11, 2011 at 3:11 answer added Henry Cohn timeline score: 139
Apr 11, 2011 at 3:06 answer added Scott Carter timeline score: 14
Apr 11, 2011 at 2:56 comment added yaoxiao According to history of mathematics, at the beginning of Bernoulli's original idea, he did not begin defined as the Taylor coefficients of the function x/(e^x-1) at 0.
Apr 11, 2011 at 2:41 history asked 36min CC BY-SA 3.0