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Apr 11, 2011 at 8:37 history edited Martin Brandenburg CC BY-SA 3.0
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Apr 11, 2011 at 8:37 vote accept Martin Brandenburg
Apr 11, 2011 at 8:37 comment added Martin Brandenburg ah, thanks! so the center is functorial with resp. to equivalences :)
Apr 10, 2011 at 20:04 comment added Tom Goodwillie If $(c,e:F(c)\to d)$ and $(c',e':F(c')\to d)$ are two such choices, then $e=e'\circ F(t)$ for some isomorphism $t:c\to c'$. Now use naturality of $s$.
Apr 10, 2011 at 19:06 comment added Martin Brandenburg Why is this independent of choices?
Apr 10, 2011 at 12:42 history answered Tom Goodwillie CC BY-SA 3.0