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Apr 10, 2011 at 23:14 answer added Peter May timeline score: 10
Apr 10, 2011 at 20:07 comment added Faisal For smooth manifolds the twisted version is also treated at the end of the first chapter of Bott & Tu.
Apr 10, 2011 at 12:32 answer added Neil Strickland timeline score: 9
Apr 10, 2011 at 11:05 answer added Johannes Ebert timeline score: 7
Apr 10, 2011 at 10:34 comment added Mark Grant Also, any closed manifold satisfies Poincaré duality when homology and cohomology are taken with coefficients in the integers mod $2$. See Hatcher (math.cornell.edu/~hatcher/AT/ATpage.html) Chapter 3.3 (the twisted version is also treated in the additional topics for Chapter 3).
Apr 10, 2011 at 8:59 comment added Torsten Ekedahl Yes, it gives an isomorphism between ordinary homology and cohomology of the local system of orientations (locally isomorphic to $\mathbb Z$) of closed manifolds. This local system is trivial precisely when the manifold is orientable.
Apr 10, 2011 at 8:44 history asked Randomblue CC BY-SA 3.0