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Apr 13, 2017 at 12:58 history edited CommunityBot
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Apr 30, 2011 at 3:11 comment added Jason @Amit: OK, so it's what I've seen as $\text{Coll}(\aleph_1, {<}\kappa)$. Thanks.
Apr 29, 2011 at 15:28 comment added Amit Kumar Gupta @Jason, I meant the Levy collapse, where each condition is a set of functions of the form $p = \{ f_{\alpha} : \alpha \in S_p\}$ where $S_p$ is a countable subset of $\kappa$ and each $f_{\alpha}$ is a countable partial function from $\omega_1$ to $\alpha$.
Apr 29, 2011 at 7:01 comment added Jason By $\text{Coll}(\kappa, \aleph_2)$, you don't mean the set of partial functions from $\aleph_2$ into $\kappa$ having size at most $\aleph_1$, do you? In this case, $U$ will not contain any subsets of $(P_{\omega_2}(\lambda))^{V[G]}$ because $j''\lambda$ will be too big. Since I would refer to that poset as $\text{Coll}(\aleph_2, \kappa)$, I'm thinking maybe you mean an Easton product $\prod_{\alpha < \kappa} \text{Coll}(\aleph_1, \alpha)$. Is this interpretation correct?
Apr 15, 2011 at 15:23 vote accept Amit Kumar Gupta
Apr 10, 2011 at 19:05 answer added Amit Kumar Gupta timeline score: 2
Apr 8, 2011 at 20:57 history edited Amit Kumar Gupta CC BY-SA 3.0
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Apr 8, 2011 at 16:14 history asked Amit Kumar Gupta CC BY-SA 3.0