Timeline for integration of a laplacian
Current License: CC BY-SA 2.5
4 events
| when toggle format | what | by | license | comment | |
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| Apr 8, 2011 at 13:46 | comment | added | WhitAngl | also, in practice (ie., on a computer), for the $H^{-1}$ norm, how can I compute the $sup$ over all $v$ with $\|v\|=1$ ? | |
| Apr 8, 2011 at 12:18 | comment | added | WhitAngl | oops, the jump is 2 in the example. I didn't mention that $H$ was the heaviside distribution as well. | |
| Apr 8, 2011 at 12:15 | comment | added | WhitAngl | I'm suprised that the distributional derivative shouldn't work : if I want to integrate $\int_{-1}^y |x|'' dx$, it corresponds to $\int_{-1}^y (H(x))'$ where I can use the jump formula to say that $H' = 0 + 1*\delta_0$ (where $1$ is the jump, and $0$ the continuous derivative), where the resulting distribution is a measure which integrates to $H(y)$. This should hold in 2D as well, and exactly corresponds to my case, isn't it ? Indeed the a posteriori error would be even better. However, if I could refine the mesh to compute it again, I would directly use the refined version. Thanks for all | |
| Apr 7, 2011 at 23:08 | history | answered | Ari | CC BY-SA 2.5 |