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Timeline for Invariant means on the integers

Current License: CC BY-SA 2.5

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Apr 7, 2011 at 13:28 comment added R W It's not a big deal. Invariance is implicit in Gabor's answer (as he talks about ultralimits of averages). Essentially, he describes the same procedure as in my answer, the only difference being that he talks about ultrafilters, whereas I prefer more old-fashioned weak limit points.
Apr 7, 2011 at 13:09 comment added Valerio Capraro Dear Gabor, it's a pleasure to hear from you! I've read a couple of your articles about sofic groups. Anyway, unfortunately I need invariant mean and ultrafilter limits are not.
Apr 7, 2011 at 11:50 comment added Emil Jeřábek Ultrafilter limits are not shift-invariant.
Apr 7, 2011 at 11:24 history answered Gabor Elek CC BY-SA 2.5