Timeline for Invariant means on the integers
Current License: CC BY-SA 2.5
11 events
| when toggle format | what | by | license | comment | |
|---|---|---|---|---|---|
| Jun 11, 2019 at 6:08 | answer | added | Yuval Peres | timeline score: 2 | |
| May 21, 2011 at 16:11 | answer | added | Andreas Thom | timeline score: 6 | |
| Apr 7, 2011 at 11:26 | answer | added | R W | timeline score: 6 | |
| Apr 7, 2011 at 11:24 | answer | added | Gabor Elek | timeline score: 7 | |
| Apr 7, 2011 at 10:27 | comment | added | Valerio Capraro | ops I've forgotten $m$ has to positive. It means that if $f$ is a positive and bounded function on $\mathbb Z$, then $m(f)\geq0$. | |
| Apr 7, 2011 at 10:19 | comment | added | camomille | Thanks for the definition. I don't know is one can edit one's comment but one can delete them (and copy/paste works on comments !). | |
| Apr 7, 2011 at 10:13 | comment | added | Valerio Capraro | and clearly for all $n\in\mathbb N$. By the way, how can I edit a comment? | |
| Apr 7, 2011 at 10:11 | comment | added | Valerio Capraro | yep, a mean is a linear functional $m:l^\infty(\mathbb Z)\rightarrow\mathbb R$ such that $m(\chi_{\mathbb Z})=1$. Invariant mean is a mean such that $m(\chi_{n+A}=m(\chi_A)$ for all $A\subseteq\mathbb Z$ | |
| Apr 7, 2011 at 10:01 | comment | added | camomille | Could you just recall what a mean is in this context ? | |
| Apr 7, 2011 at 9:04 | history | edited | Yemon Choi |
added func-an tag
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| Apr 7, 2011 at 7:23 | history | asked | Valerio Capraro | CC BY-SA 2.5 |