Timeline for Basic question about branch points on Riemann surfaces
Current License: CC BY-SA 2.5
7 events
| when toggle format | what | by | license | comment | |
|---|---|---|---|---|---|
| Apr 25, 2020 at 2:38 | comment | added | Lasse Rempe | Just make it $(sin z)^2/z$ and 0 is also a critical value ... | |
| Apr 6, 2011 at 0:23 | comment | added | Tom Goodwillie | $e^{i(\alpha x+sin(x))}$ where $\alpha$ is irrational and between $0$ and $1$. | |
| Apr 5, 2011 at 22:36 | comment | added | Tom Goodwillie | George, you are right. I was not paying attention and was thinking "closed and discrete" rather than "discrete". | |
| Apr 5, 2011 at 20:50 | comment | added | Georges Elencwajg | Dear Tom, according to my calculations, the branch points of your function do form a discrete set, with $0$ not a branch point but the unique point of accumulation of that branch locus. [ I may have made a stupid mistake, of course. Do you agree that the the set of critical points is $-\pi /4+ \pi \mathbb Z$ ?] | |
| Apr 5, 2011 at 20:42 | comment | added | Georges Elencwajg | Dear Johannes, I had thought of that function, but it was not clear to me that the set of branch points is not discrete. How do you show that ? | |
| Apr 5, 2011 at 19:27 | comment | added | Tom Goodwillie | Yes, or $f:\mathbb C\to \mathbb C$, $f(z)=e^zsin z$. | |
| Apr 5, 2011 at 19:20 | history | answered | Johannes Ebert | CC BY-SA 2.5 |