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Apr 5, 2011 at 22:37 comment added Noah Giansiracusa Indeed, it is a nice paper. The Chow quotient maps to all the GIT quotients, so the polarizations on the latter pull back to the former, namely M_{0,n}, but the Chow-GIT morphisms are contractions (for n > 6), so come from nef but not ample divisors. So the Alexeev-Swinarski divisors cannot be the Hilbert or Chow polarizations (though perhaps their convex hull contains these ample divisors?...)
Apr 5, 2011 at 20:55 comment added J.C. Ottem There are some papers on this question. For starters, have you seen Alexeev and Swinarski's paper math.uga.edu/~davids/0812.0778.pdf?
Apr 5, 2011 at 15:06 history asked Noah Giansiracusa CC BY-SA 2.5