Timeline for There is no lattice in PSL(2,R) which contains PSL(2,Z) properly?
Current License: CC BY-SA 3.0
14 events
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Aug 24, 2013 at 11:09 | comment | added | C.S. | @DavidLoeffler It's quite surprising that Modular forms are taught at the undergraduate level. Wouldn't it be too hard on students? | |
Apr 5, 2012 at 19:06 | answer | added | Igor Rivin | timeline score: 10 | |
Apr 5, 2012 at 17:42 | answer | added | Jim Humphreys | timeline score: 3 | |
Apr 5, 2012 at 17:19 | history | edited | Jim Humphreys |
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Apr 5, 2012 at 11:38 | history | edited | Marc Palm | CC BY-SA 3.0 |
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Mar 15, 2012 at 18:39 | history | edited | Guntram | CC BY-SA 3.0 |
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Apr 7, 2011 at 7:55 | vote | accept | Marc Palm | ||
Apr 5, 2011 at 7:57 | answer | added | S. Carnahan♦ | timeline score: 12 | |
Apr 5, 2011 at 7:38 | history | edited | Marc Palm | CC BY-SA 2.5 |
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Apr 5, 2011 at 7:38 | comment | added | Marc Palm | So I guess, it is reasonable for $G$ reductive!? | |
Apr 5, 2011 at 7:25 | comment | added | David Loeffler | I remember setting this (or, rather, the same question with SL(2) in place of PSL(2)) as an exercise to an undergraduate modular forms class once. Nobody solved it :-) If I remember correctly, the argument goes: first convince yourself that any such lattice must be contained in PSL(2, Q); then use the fact that PSL(2, Zp) is maximal compact in PSL(2, Qp) for every prime p. | |
Apr 5, 2011 at 7:19 | history | edited | Marc Palm | CC BY-SA 2.5 |
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Apr 5, 2011 at 7:14 | history | edited | Marc Palm | CC BY-SA 2.5 |
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Apr 5, 2011 at 7:08 | history | asked | Marc Palm | CC BY-SA 2.5 |