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Timeline for Is $\zeta(3)/\pi^3$ rational?

Current License: CC BY-SA 4.0

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S May 8 at 5:02 history suggested Ukhukanya CC BY-SA 4.0
The Apery paper was in 1979
May 8 at 3:23 review Suggested edits
S May 8 at 5:02
Sep 1, 2019 at 18:51 comment added Lucian Intuitively speaking, all $\zeta(2n)$ are sums of squares, as is also the algebraic equation of the circle, $x^2+y^2=r^2,~$ whose constant $\pi$ is.
Feb 8, 2017 at 1:53 comment added Gerry Myerson Question also arose at m.se, math.stackexchange.com/questions/35412/…
Aug 18, 2016 at 5:16 comment added Jonas Meyer @NoamD.Elkies: I was unclear. "this" meant the one asked here, not the one referred to previously in that sentence.
Aug 18, 2016 at 1:24 comment added Noam D. Elkies @JonasMeyer "$\zeta(3)$ is algebraically independent of $\pi$" is a much stronger conjecture than $\zeta(3)$ is not a rational multiple of $\pi^3$, so naturally the algebraic independence is not known either.
Aug 18, 2016 at 0:54 comment added Per Alexandersson Perhaps one can ask if $\zeta(3)^a/\zeta(5)^b$ is rational for some pair of positive integers $(a,b)$...
S Aug 18, 2016 at 0:22 history suggested CommunityBot CC BY-SA 3.0
fixed mathjax formatting
Aug 18, 2016 at 0:12 review Suggested edits
S Aug 18, 2016 at 0:22
May 9, 2011 at 21:40 answer added AFK timeline score: 6
May 9, 2011 at 20:58 answer added DamienC timeline score: 21
May 9, 2011 at 14:35 answer added user02138 timeline score: 15
Apr 5, 2011 at 0:20 answer added Gerry Myerson timeline score: 27
Apr 4, 2011 at 21:38 comment added Ramsey Just to expand on Kevin's answer in a way that might help you to do some relevant searches: the positive even integers and negative odd integers are "critical integers" for the motive of which $\zeta(s)$ is the associated motivic $L$-function (namely, $Spec(\mathbb{Q})$). These are the ones to which a conjecture of Deligne applies that "explains" why $\zeta(k)\pi^{-k}\in \mathbb{Q}$ for positive even $k$.
Apr 4, 2011 at 21:11 answer added Gerald Edgar timeline score: 7
Apr 4, 2011 at 20:15 comment added Kevin Buzzard It's actually not natural to ask whether $\zeta(3)$ is a rational multiple of $\pi^3$! There are "natural" conjectures to make about special values of a huge class of zeta functions, including Riemann's, and once you have figured out what's going on then you realise that the (conjectural) story for Riemanns zeta should be quite different at odd and even integers. Evidence for this: look at the values of Riemann's zeta at negative integers! it always vanishes at $-2,-4,-6,\ldots$ and never vanishes at $-1,-3,-5,\ldots$.
Apr 4, 2011 at 19:43 comment added Faisal Also relevant: mathoverflow.net/questions/38190/…
Apr 4, 2011 at 19:39 comment added Jonas Meyer You may find mathoverflow.net/questions/30659/… useful, with a relevant comment by Wadim Zudilin and answer by Emerton. It is conjectured algebraically independent of $\pi$, but it doesn't seem that even this weaker result is known.
Apr 4, 2011 at 19:27 history asked Thomas Bloom CC BY-SA 2.5