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Apr 11, 2014 at 16:04 history edited Michael Hardy CC BY-SA 3.0
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Apr 7, 2011 at 13:50 vote accept Haining Yu
Apr 7, 2011 at 13:50
Apr 1, 2011 at 13:34 comment added David Harris Suppose that the V are normally distributed (not necessarily independent). Then for any choice of $\theta_k$, the resulting $X$ is normally distributed with mean and variance depending on $\theta$. There is no such thing as the "correct" $\theta$.
Mar 31, 2011 at 20:48 comment added Haining Yu Thanks for the comment. I see there are possibility for multiple identification issues. First on the scaling issue: in my real problem I have ways to prevent $\mu$ and $\sigma$ from cancelling each other. In fact I can set $\mu$ to a constant. I am indeed more concerned by the relationship between $X$ and $V$. For example, assume $ X = sum_{k}{v_k\theta_k} + c $ where $c$ is a non-zero constant. When I have a large (or infinite) number of samples, $\theta$ should be unique identified?
Mar 31, 2011 at 20:29 history answered David Harris CC BY-SA 2.5