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Mar 30, 2011 at 7:19 vote accept bobye
Mar 29, 2011 at 19:22 answer added Otis Chodosh timeline score: 2
Mar 29, 2011 at 11:55 history edited bobye CC BY-SA 2.5
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Mar 29, 2011 at 11:44 history edited bobye CC BY-SA 2.5
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Mar 29, 2011 at 11:42 comment added bobye Sorry, I failed to express my idea. My focus is about local structure, I misuse the concept of quasi-isometry. However I did not found a way to describe which two manifold are "almost" isometric. For example, the bounding surfaces of a non-rigid object may be "near" isometric of different poses. Their spectrum data seems be continuously change with respect to pose change. The deformation of a metric space will have corresponding change of their spectrum data. For two metric, considering their map $f$. inf{e: |d(x,y)-d(f(x),f(y)|< e} estimate compute min w.r.t $f$
Mar 29, 2011 at 11:38 answer added ght timeline score: 4
Mar 29, 2011 at 11:19 comment added Paul Siegel I don't think you're asking the right question: the theory of isospectral manifolds generally focuses on closed manifolds, but any two compact metric spaces are automatically quasi-isometric. Quasi-isometries don't care at all about local structure - they are best adapted to large scale problems involving non-smooth spaces. So it's hard to imagine what the sort of connection that you're asking about would look like.
Mar 29, 2011 at 5:02 history asked bobye CC BY-SA 2.5