Timeline for are there infinitely many triples of consecutive square-free integers?
Current License: CC BY-SA 2.5
6 events
| when toggle format | what | by | license | comment | |
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| Mar 5, 2013 at 14:51 | comment | added | Charles | Dickson's conjecture does apply, you just have to use (say) 12n+1, 6n+1, and 4n+1. But that's a pretty big sledgehammer to apply to a little problem like this! | |
| Apr 1, 2011 at 23:01 | comment | added | Yemon Choi | Well, "disputandum" | |
| Mar 27, 2011 at 18:28 | comment | added | user9072 | Unnecessarily involved?? De gustibus non est dispudandum... | |
| Mar 27, 2011 at 18:15 | comment | added | Ewan Delanoy | @Zander : I corrected the Dickson conjecture part, thanks. | |
| Mar 27, 2011 at 18:14 | comment | added | Ewan Delanoy | @ Zander : Erick Wong's argument is correct, but actually it's an unnecessarily involved variant of George Lowther's, and it does not yield the density of the set of solutions (the product of 1-(3/(p^2))). | |
| Mar 27, 2011 at 17:55 | history | answered | Zander | CC BY-SA 2.5 |