Timeline for nontrivial cube root of unity
Current License: CC BY-SA 2.5
7 events
| when toggle format | what | by | license | comment | |
|---|---|---|---|---|---|
| Mar 26, 2011 at 16:48 | vote | accept | Niti | ||
| Mar 26, 2011 at 16:48 | comment | added | Niti | Thank you very much! I got it now. You are my hero. Anyway I am surprised why all of you get so uppset. I made some errors but... I am just trying to learn. | |
| Mar 26, 2011 at 13:34 | comment | added | Charles Matthews | Sigh. Like in en.wikipedia.org/wiki/Root_of_unity#Examples. The formula you are proposing mimics that formula, but it is all over the factor 2. Anyway I guess I gave the wrong reason about the square root of 3, since quadratic reciprocity should enter. But like everyone said, MO is the wrong forum; and your statement had a couple of errors also. | |
| Mar 26, 2011 at 12:49 | comment | added | Niti | lets say z^3=1. Then z in complex (Re{z} + i* Im{z}): Re{z} = (p-1)/2, Im{z} = 3^((p+1)/4) mod(p) | |
| Mar 26, 2011 at 11:14 | comment | added | Charles Matthews | Please write down the formula for a complex cube root of unity. | |
| Mar 26, 2011 at 10:52 | comment | added | Niti | Hi Charles, where exactly do you think the 2 is missing? | |
| Mar 25, 2011 at 19:56 | history | answered | Charles Matthews | CC BY-SA 2.5 |