Timeline for Example of an infinite index subgroup of a non-amenable group whose normalizer is of non-zero finite index, and such that the Schreier graph is of subexponential growth [closed]
Current License: CC BY-SA 2.5
26 events
| when toggle format | what | by | license | comment | |
|---|---|---|---|---|---|
| Apr 13, 2017 at 12:58 | history | edited | CommunityBot |
replaced http://mathoverflow.net/ with https://mathoverflow.net/
|
|
| Apr 16, 2014 at 21:04 | history | closed |
YCor Lucia Stefan Kohl♦ Yemon Choi Jeremy Rickard |
Not suitable for this site | |
| Apr 16, 2014 at 16:44 | comment | added | Lucia | Voting to close as no longer relevant per request of OP. | |
| Apr 16, 2014 at 16:41 | review | Close votes | |||
| Apr 16, 2014 at 21:04 | |||||
| Mar 28, 2011 at 15:03 | comment | added | Kate Juschenko | @Lukasz: the positive factor is that the new question attracted much more people comparing with this one | |
| Mar 28, 2011 at 15:00 | comment | added | Kate Juschenko | @Lukasz: thanks for reverting! I see so many posts, where people are changing original questions to something else. Usually it becomes a big mess, where it is not clear who answers what and why... | |
| Mar 23, 2011 at 16:09 | comment | added | Łukasz Grabowski | @Kate: I'll ask a seperate question about the eqivalence realation. | |
| Mar 23, 2011 at 16:09 | history | edited | Łukasz Grabowski | CC BY-SA 2.5 |
added 341 characters in body
|
| Mar 23, 2011 at 15:50 | comment | added | Kate Juschenko | Could you please give more details the property of equivalence relations that you are looking for and the connection to the question (new one). Since I don't see how to produce such a measure... | |
| Mar 23, 2011 at 15:44 | vote | accept | Łukasz Grabowski | ||
| Mar 23, 2011 at 15:44 | comment | added | Łukasz Grabowski | Ok, I reverted. | |
| Mar 23, 2011 at 15:43 | history | rollback | Łukasz Grabowski |
Rollback to Revision 4
|
|
| Mar 23, 2011 at 15:31 | history | edited | Łukasz Grabowski | CC BY-SA 2.5 |
edited title
|
| Mar 23, 2011 at 15:24 | history | edited | Łukasz Grabowski | CC BY-SA 2.5 |
added 220 characters in body
|
| Mar 23, 2011 at 15:11 | comment | added | Kate Juschenko | @Lukasz: I've modified the example to get index strictly greater then 1. | |
| Mar 22, 2011 at 17:15 | history | edited | Łukasz Grabowski | CC BY-SA 2.5 |
added 8 characters in body
|
| Mar 22, 2011 at 17:15 | comment | added | Łukasz Grabowski | @Igor, Thanks, I learned something today :-). I'll edit the question | |
| Mar 22, 2011 at 15:42 | answer | added | Kate Juschenko | timeline score: 9 | |
| Mar 22, 2011 at 15:32 | comment | added | Igor Rivin | I assume "non-zero" is code for "greater than one"?! | |
| Mar 22, 2011 at 15:04 | comment | added | Łukasz Grabowski | @Kate: as I wrote, index of $N(H)$ should be non-zero finite, so this isn't a good example | |
| Mar 22, 2011 at 14:34 | comment | added | Kate Juschenko | Maybe you mean normal closure instead of normalizer? Normalizer of the normal group is the whole group, in that case the answer to your question is $G=H\times \mathbb{Z}$, since $N(H)=G$ in this case. | |
| Mar 22, 2011 at 13:34 | history | edited | Łukasz Grabowski | CC BY-SA 2.5 |
added 78 characters in body
|
| Mar 22, 2011 at 12:22 | comment | added | Łukasz Grabowski | out of such an example one can construct a faithful probability measure preserving action of a non-ameanable group, with an ameanable equivalence relation. Besides, I'd be happy to learn what techniques can say something about "amenability" of the quotient G/H when H is not normal. | |
| Mar 22, 2011 at 11:20 | comment | added | Kate Juschenko | what is the motivation of this question? | |
| Mar 22, 2011 at 11:12 | history | edited | Charles Matthews | CC BY-SA 2.5 |
spelling
|
| Mar 22, 2011 at 11:06 | history | asked | Łukasz Grabowski | CC BY-SA 2.5 |