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Mar 23, 2011 at 11:59 comment added Bjørn Kjos-Hanssen @Tanmay: apparently they show NCR$_n$ is properly $\mathbf\Pi^1_1$ as soon as there are not enough power sets (and countable hence $\mathbf\Sigma^0_2$ when there are).
Mar 22, 2011 at 17:10 comment added KConrad This example is missing the condition in the statement of the problem that any graduate student can think about it, although I'll grant you that they'd still not have an answer after 10 minutes.
Mar 22, 2011 at 14:16 comment added user3462 So, depending on how many iterates you have, you can go from $\Pi_{1}^{1}\setminus\Delta_{1}^{1}$ to $\Sigma_{2}^{0}$? (Wow!)
Mar 22, 2011 at 12:57 comment added user3462 Bjørn, does the Borel rank of the NCR$_n$ change depending on how many iterates of the power set of the natural numbers are assumed?
Mar 22, 2011 at 2:14 history answered Bjørn Kjos-Hanssen CC BY-SA 2.5