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Jul 16, 2013 at 12:49 comment added Zsbán Ambrus @NoahS: True, thanks for the explanation.
Jul 16, 2013 at 11:52 comment added Noah Schweber By the compactness theorem, since $\phi$ is a consequence of $T$ we know that $\phi$ is a consequence of some finite $T'\subset T$; this $T'$ can only contain finitely many $\chi_j$, so in fact $\phi$ is a consequence of the characteristic of the algebraically closed field being at least $n$ for $n=\max\lbrace j: \chi_j\in T'\rbrace$. (Incidentally, this also proves that we only need roots of polynomials of sufficiently large degree!)
Jul 16, 2013 at 11:51 comment added Noah Schweber @Zsban: Yes. Suppose $\phi$ is a first-order sentence true in all algebraically closed fields of characteristic zero. The set of algebraically closed fields of characteristic zero is the set of models of $T=\lbrace \psi\rbrace\cup\lbrace \theta_i: i\in\omega\rbrace\cup\lbrace \chi_j: j\in\omega\rbrace$, where $\psi$ is the field axiom(s), $\theta_i$ asserts that all degree-$i$ polynomials have roots, and $\chi_j$ asserts that the characteristic is at least $j$. (cont'd)
Jul 16, 2013 at 8:01 comment added Zsbán Ambrus @MartinBrandenburg: logic proves the if part, but does it also prove the only if part?
Apr 4, 2013 at 0:18 history edited Daniel Miller CC BY-SA 3.0
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Mar 24, 2011 at 3:22 history made wiki Post Made Community Wiki by Kim Morrison
Mar 22, 2011 at 17:11 comment added Donu Arapura While I also agree that the logic proofs are simpler in this case (I'd probably use ultraproducts myself), the technique of specializing into characteristic $p$ can pushed much further, and scheme theory provides a very powerful language for this.
Mar 22, 2011 at 9:31 comment added Martin Brandenburg But this is just an application of the compactness theorem in mathematical logic!
Mar 21, 2011 at 23:12 comment added Thierry Zell I find this application especially nice.
Mar 21, 2011 at 20:18 history answered Dustin Clausen CC BY-SA 2.5