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Mar 20, 2011 at 0:28 comment added Olivier Bégassat can you explain please? I looked up "fixed points of Moebius transforms" and only found that (the non identity ones) they either fix two points on the boundary $\partial\mathbb{H}$, one point on the boundary and no other, or two points in $\mathbb{H}$
Mar 19, 2011 at 6:49 history answered Jack Rousseau CC BY-SA 2.5