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Jan 12, 2022 at 20:10 comment added Z. M Sorry for a silly question: it seems to me that Deligne–Illusie is about lifting along $S\to\tilde S$ where $\tilde S$ is $\mathbb Z/p^2$-flat and $\tilde S\otimes_{\mathbb Z/p^2}\mathbb F_p\cong S$, not $W_2(S)$ (unless $S$ is perfect)?
May 14, 2011 at 18:26 comment added Matt @Torsten Ekedahl Since this is an old thread, no one will probably look at this, but I wonder if you impose the condition that the CY variety be of finite height (i.e. not supersingular) if you get degeneration of the HdRSS. The example in your paper has infinite height.
Mar 23, 2011 at 16:27 history edited Torsten Wedhorn CC BY-SA 2.5
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Mar 23, 2011 at 11:42 comment added Torsten Ekedahl It is not clear that this is related to char 2. In arXiv:math/0306435 I compute the Hodge s.s. of an example of Schröer in char 3 which has trivial canonical bundle and non-degenerate Hodge s.s.
Mar 23, 2011 at 8:30 vote accept Torsten Wedhorn
Mar 23, 2011 at 8:28 history edited Torsten Wedhorn CC BY-SA 2.5
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Mar 23, 2011 at 8:22 comment added Torsten Wedhorn @Torsten Ekedahl: Yes, thank you. I had not thought that the triviality of the canonical bundle is not a good definition for CY in characteristic 2. I edited d).
Mar 21, 2011 at 19:22 comment added Torsten Ekedahl d) needs some extra condition as is shown by a s.s. Enriques surface in char 2. (It should probably not qualify as Calabi-Yau somehow.)
Mar 21, 2011 at 15:54 answer added Donu Arapura timeline score: 11
Mar 19, 2011 at 16:25 history edited Torsten Wedhorn CC BY-SA 2.5
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Mar 18, 2011 at 19:03 history edited Torsten Wedhorn CC BY-SA 2.5
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Mar 18, 2011 at 14:41 comment added Donu Arapura This is a good question. I don't know many examples beyond the ones you listed. Things like Grassmanian bundles can be added to b. More generally, any time the Hodge numbers are concentrated along the diagonal ($h^{pq}=0$ for $p\not= q$), the spectral sequence trivially degenerates.
Mar 18, 2011 at 12:36 history asked Torsten Wedhorn CC BY-SA 2.5