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Post Closed as "too localized" by Andreas Blass, Tyler Lawson, S. Carnahan
added 60 characters in body; deleted 48 characters in body; deleted 5 characters in body; edited title
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Ehsan M. Kermani
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Is $X$ homeomorphic to $S^1 \times Y$ where $Y$ is a contractible topological space?

Is it true that when the first fundamental group of a topological space $X$ is isomorphic to $\mathbb{Z}$ then $X$ is homeomorphic to $S^1 \times Y$ where the first fundamental group of $Y$ is a contractible topological spacetrivial?

With a discussion with my of friends, the above question turned into (!) finding a topological space $X$ s.t. there is no quotient space obtained from $X$ being homeomorphic to $S^1.$

Is $X$ homeomorphic to $S^1 \times Y$ where $Y$ is a contractible topological space?

Is it true that when the first fundamental group of a topological space $X$ is isomorphic to $\mathbb{Z}$ then $X$ is homeomorphic to $S^1 \times Y$ where $Y$ is a contractible topological space?

With a discussion with my of friends, the above question turned into (!) finding a topological space $X$ s.t. there is no quotient space obtained from $X$ being homeomorphic to $S^1.$

Is $X$ homeomorphic to $S^1 \times Y$?

Is it true that when the first fundamental group of a topological space $X$ is isomorphic to $\mathbb{Z}$ then $X$ is homeomorphic to $S^1 \times Y$ where the first fundamental group of $Y$ is trivial?

With a discussion with my of friends, the above question turned into (!) finding a topological space $X$ s.t. there is no quotient space obtained from $X$ being homeomorphic to $S^1.$

Source Link
Ehsan M. Kermani
  • 1.7k
  • 1
  • 16
  • 19

Is $X$ homeomorphic to $S^1 \times Y$ where $Y$ is a contractible topological space?

Is it true that when the first fundamental group of a topological space $X$ is isomorphic to $\mathbb{Z}$ then $X$ is homeomorphic to $S^1 \times Y$ where $Y$ is a contractible topological space?

With a discussion with my of friends, the above question turned into (!) finding a topological space $X$ s.t. there is no quotient space obtained from $X$ being homeomorphic to $S^1.$