Timeline for Is this (interpolation) inequality right?
Current License: CC BY-SA 2.5
8 events
| when toggle format | what | by | license | comment | |
|---|---|---|---|---|---|
| Mar 19, 2011 at 14:46 | vote | accept | jack | ||
| Mar 16, 2011 at 10:36 | answer | added | TaQ | timeline score: 2 | |
| Mar 16, 2011 at 1:30 | comment | added | jack | Thanks for you all. $F$ is bounded in $L^\infty (0,T;\Omega)$ and $L^{5/3}(0,T;C^k(\bar{\Omega}))$ for all $k\in\mathbb{N}_0$. I have edit the statement. | |
| Mar 16, 2011 at 1:20 | history | edited | jack | CC BY-SA 2.5 |
deleted 9 characters in body; deleted 9 characters in body; edited body; added 3 characters in body
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| Mar 16, 2011 at 1:01 | comment | added | TaQ | By considering functions like $(t,s)\mapsto\sin(t^{-r}s)$ , it also seems obvious that if the assumption holds (only) for some $k\ge 2$ , then the question cannot be answered positively for $q>\frac 56 k$ . | |
| Mar 16, 2011 at 0:42 | comment | added | TaQ | By "for an arbitrary integer $k\ge 0$ " do you mean that it holds for some fixed $k\in\mathbb N_0$ or for all such? By "for any $q\in[1,\infty)$ " do you mean that it should hold for some such $q$ or for all? Of course, if in the assumption we take $k$ at least $2$ , then to the question we can answer positively for $1\le q\le\frac 53$ . | |
| Mar 15, 2011 at 14:24 | comment | added | Michael Renardy | Something is misstated here. Did you mean $k\ge 2$? Or should it be $L^q(0,T;C(\bar\Omega))$? | |
| Mar 15, 2011 at 13:39 | history | asked | jack | CC BY-SA 2.5 |