Timeline for Intersections of conjugates of Lie subgroups
Current License: CC BY-SA 2.5
13 events
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Apr 13, 2017 at 12:58 | history | edited | CommunityBot |
replaced http://mathoverflow.net/ with https://mathoverflow.net/
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Feb 3, 2012 at 10:09 | vote | accept | Mark Grant | ||
Mar 21, 2011 at 15:04 | history | edited | Mark Grant | CC BY-SA 2.5 |
added link to new question
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Mar 18, 2011 at 10:49 | history | edited | Mark Grant | CC BY-SA 2.5 |
Asked follow-up question
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Mar 14, 2011 at 7:56 | answer | added | agt | timeline score: 1 | |
Mar 13, 2011 at 13:25 | comment | added | Mark Grant | Thanks Giuseppe. In my applications $G$ is connected, but your comment shows I was being too optimistic (as does Jack's connected answer). | |
Mar 13, 2011 at 13:21 | answer | added | Jim Humphreys | timeline score: 2 | |
Mar 13, 2011 at 13:21 | history | edited | Mark Grant | CC BY-SA 2.5 |
typo
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Mar 13, 2011 at 10:40 | answer | added | Jack Schmidt | timeline score: 4 | |
Mar 13, 2011 at 10:19 | comment | added | agt | If you consider groups whose cardinality is less than or equal to $\aleph_0$ and endow them with the discrete topology, then you get 0-dimensional Lie groups. Now take $G=S_n$ the symmetric group of $\{1,\ldot,n\},$ and $H_i$ the subgroup of the permutations fixing $i,$ for $i=1,\ldots,n$ these are obviously conjugate each other. Trivially $H_1\cap H_2$ is not conjugate to $H_1$. Excuse me if this answer is not what you wanted. | |
Mar 13, 2011 at 10:01 | history | edited | Mark Grant | CC BY-SA 2.5 |
typos
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Mar 13, 2011 at 9:56 | comment | added | agt | Excuse me, but in the last line, shouldn't there be ${}^aH\cap{}^bH$ instead of ${}^aH={}^bH$ ? or not? | |
Mar 13, 2011 at 9:24 | history | asked | Mark Grant | CC BY-SA 2.5 |