Timeline for Nonexistence of projection
Current License: CC BY-SA 2.5
16 events
| when toggle format | what | by | license | comment | |
|---|---|---|---|---|---|
| Mar 14, 2011 at 5:42 | comment | added | Sándor Kovács | @John Jiang: I took it lightheartedly and thought it was OK. At the same time I wanted to make the point that my goal in posting an answer is not motivated by enhancing my reputation. Then again, I totally understand your point and find nothing wrong with it. And I agree that I can easily say that I don't care about enhancing my reputation when it is already enhanced. Cheers! | |
| Mar 14, 2011 at 5:38 | comment | added | Sándor Kovács | Let me add, that unfortunately it is really hard to convey one's mood in a comment and one often reads something into what someone else wrote that the other person did not mean. An innocent comment may seem offensive for another person and can lead to bad feelings. I definitely did not mean to do that to you! :) | |
| Mar 14, 2011 at 5:36 | comment | added | Sándor Kovács | Dear Ashok, there is no reason to be ashamed, the point of this website (I think) is to help each other's understanding of mathematics. We all commit mistakes (I definitely do that a lot!) and overlook things. No harm in that. Take care! | |
| Mar 14, 2011 at 5:00 | comment | added | Ashok | @Sándor: Indeed. I feel ashamed. | |
| Mar 14, 2011 at 4:53 | vote | accept | Ashok | ||
| Mar 14, 2011 at 4:53 | |||||
| Mar 14, 2011 at 0:18 | comment | added | John Jiang | @Sandor and Suvrit: Light-hearted indeed. I have never gotten a single correct answer before so would like to see how many points it's worth:) | |
| Mar 13, 2011 at 17:27 | comment | added | Sándor Kovács | @Suvrit: I thought the idea was to answer questions, not enhancing our reputations. :) | |
| Mar 13, 2011 at 17:26 | comment | added | Sándor Kovács | @Ashok: It was not clear from your question that this is what you're after. The positive part is not a space. The idea works the same way, just change $b$ to say $2$. That changes $L$ to the set of elements in the form $(a+2,a)$ with $a>0$ and $u=(1,1)$ works (taking $-u$ and shifting both $L$ and $u$ by $(2,0)$. I wrote down the principle that matters. Apparently you did not get that part. Cheers! | |
| Mar 13, 2011 at 13:48 | comment | added | Ashok | would it be better to start a new post for the further question? | |
| Mar 13, 2011 at 12:53 | comment | added | Ashok | Yes Suvrit, but the point is that the $u$ in Sándor Kovács's example lies outside my space of interest $\mathbb{R}_+^n$. I am wondering whether one can still find an example even if we relax the strictly positiveness to non negativeness. | |
| Mar 13, 2011 at 12:32 | comment | added | Suvrit | @Ashok: Sándor mentions the key term: "not closed" | |
| Mar 13, 2011 at 12:32 | comment | added | Suvrit | I think what John Jiang means is: "Sándor already has high reputation score, and does not need to enhance his rep further by answering such simple questions." However, I think that was probably (i hope) meant in an light-hearted sense ;-) | |
| Mar 13, 2011 at 12:29 | comment | added | Ashok | I too tried for the same $L$. Though $u\notin L$ I wanted the vector $u$ to be in the space we consider namely $\mathbb{R}_+^n$. So this doesn't serve as an example. Thanks any way! | |
| Mar 13, 2011 at 9:46 | comment | added | Georges Elencwajg | @John Jiang: ?? | |
| Mar 13, 2011 at 4:52 | comment | added | John Jiang | Haha, looks like you are in less need for a point booster. | |
| Mar 13, 2011 at 4:45 | history | answered | Sándor Kovács | CC BY-SA 2.5 |