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Mar 13, 2011 at 12:34 comment added Suvrit a minor point: the notation is somewhat unfortunate, because normally one would expect $d(A,A)$ to be zero (notationally speaking).
Mar 13, 2011 at 11:12 vote accept Dair T'arg
Mar 13, 2011 at 4:27 history edited Yemon Choi
changed tags
Mar 13, 2011 at 4:26 comment added Yemon Choi By the way, "measure-theory" refers to something specific which is not the same as what you are talking about. I've taken the liberty of changing the tags
Mar 13, 2011 at 2:46 answer added noppoli timeline score: 3
Mar 13, 2011 at 1:14 history edited Dair T'arg CC BY-SA 2.5
improved formatting
Mar 13, 2011 at 1:04 history asked Dair T'arg CC BY-SA 2.5