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Jun 30 at 16:01 comment added S. Carnahan @KasperAndersen Thank you, that is correct.
Jun 30 at 16:01 history edited S. Carnahan CC BY-SA 4.0
added square root following comment
Jun 29 at 8:58 comment added Kasper Andersen Shouldn't this be $\sqrt{2\pi}$ in the numerator?
Mar 22, 2011 at 19:45 vote accept 7-adic
Mar 12, 2011 at 15:43 comment added S. Carnahan That seems to be a reasonably likely explanation. I just Googled for Pochhammer asymptotic, and didn't bother to think too much.
Mar 12, 2011 at 15:20 comment added Julien Puydt I would say that equivalent was obtained through the generalized Stirling formula for the $\Gamma$ function, as pointed to by Yemon Choi.
Mar 12, 2011 at 5:48 history answered S. Carnahan CC BY-SA 2.5