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Jun 14, 2011 at 19:33 answer added Asaf timeline score: 5
Jun 13, 2011 at 21:30 history edited Ostap Chervak
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Apr 4, 2011 at 15:41 comment added Charles Presumably Nick meant 'irrational unless the (reduced) denominator is a power of two' to exclude trivial cases like 17.
Apr 3, 2011 at 20:59 history edited Ostap Chervak
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Mar 11, 2011 at 18:02 history edited Ostap Chervak CC BY-SA 2.5
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Mar 11, 2011 at 13:49 vote accept Ostap Chervak
Mar 11, 2011 at 4:51 comment added Gerry Myerson @Nick, why must $\alpha$ be irrational? If $\alpha$ is, say, 17, then there are certainly integers $n$ such that $\alpha n^2$ is within $\epsilon$ of an integer (ditto for $2^n\alpha$ or $F_n\alpha$).
Mar 11, 2011 at 1:17 comment added Nick S $\alpha$ has to be irational.
Mar 11, 2011 at 0:35 answer added Nikita Sidorov timeline score: 12
Mar 10, 2011 at 23:31 answer added Gerry Myerson timeline score: 7
Mar 10, 2011 at 22:53 history asked Ostap Chervak CC BY-SA 2.5