Timeline for Subgroups of free abelian groups are free: a topological proof?
Current License: CC BY-SA 2.5
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| when toggle format | what | by | license | comment | |
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| Oct 28, 2015 at 15:37 | review | Low quality posts | |||
| Oct 28, 2015 at 17:15 | |||||
| Nov 17, 2009 at 4:31 | comment | added | Tom Church | Because the subgroups of homology don't correspond to subgroups of the free group in the way you want. If V is a subgroup of Z^n, the corresponding subgroup G of F_n has infinite-rank first homology whenever V has infinite index. | |
| Nov 17, 2009 at 3:39 | history | answered | Andrew S | CC BY-SA 2.5 |