Skip to main content

Timeline for Can infinity shorten proofs a lot?

Current License: CC BY-SA 2.5

7 events
when toggle format what by license comment
Nov 17, 2009 at 22:52 history edited Qiaochu Yuan CC BY-SA 2.5
Changed an example.
Nov 17, 2009 at 22:51 comment added Qiaochu Yuan Never mind; you can prove the statement by induction, so that was a bad example.
Nov 17, 2009 at 22:41 comment added Qiaochu Yuan I guess what I meant to say is I don't know of a finitary proof, but now that I think about it, that might not be true. Hmm.
Nov 17, 2009 at 21:22 comment added gowers You can get the inequality quite easily I think. The log of n! is the sum of log m from 1 to n, which is at least the integral from 1 to n of log x, which is nlogn-n. Done.
Nov 17, 2009 at 20:53 comment added Konrad Swanepoel You can get $n! \geq n^n/e^n$ just by looking at the Taylor series of $e^x$, but that is perhaps still not hands on.
Nov 17, 2009 at 0:14 comment added Harrison Brown The elementary proof is far tougher to slog through, although there's a bunch of background hidden in the complex-analytic proof which makes it probably about as hard to learn "from scratch."
Nov 16, 2009 at 23:51 history answered Qiaochu Yuan CC BY-SA 2.5